Of course, you may then ask what is the sum to infinite terms, or the sum to infinity for this series, and we can then represent it as such:
The previous post dealt with the problem of 0.11111… as a recurring decimal using the idea of a Geometric Progression, and I’m about to show you exactly how right now.
First of all, let us consider the sum to n terms (this is often called the partial sum of the first n terms):
First of all, let us consider the sum to n terms (this is often called the partial sum of the first n terms):
It must then be agreeable and logical that if I multiply this by the common ratio r, I obtain:
Taking the difference of the two, I see that:
And rearranging, I immediately see that:
Now what is the sum to infinity then? Easy, it can be evaluated by considering the limit as n tends towards infinity:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjW3os88VMWp4cMEuEyIHrDyp2_3abjDTs15MEvXBttMrWL48_M4kZ74PN1SLdxUK8MlVy5B1NYTMno-ADIIoD2DYiNWh0Q75QryQK-T7qSmX_ndH_QrQrkLm1nYOJiE561ni_wTTXJG8S5/s400/008.JPG)
Notice that this limit can only exist, if the common ratio r has a magnitude smaller than one, such that it decreases to effectively zero for huge values of n:
With this in mind, the sum to infinity is simply:
So applying this to the previous problem, we see that:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiuJ0u9jyLG2-pHmES3CvMU8nh34P-BcpMWhiXuuBIgrN0a3OVuf2rJ9dsPRdpq4Sw5LM8GZfdTuLvJ8LySG0_FArzwkVHxTR-wgXon12prWfrNfH5ndG_Vc2xRXaq30nB2N2aaZE7jbRNA/s400/011.JPG)
And therefore there is no actual need for any algebraic manipulation to solve for recurring numbers once you have grasped this theory. :)
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